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100x^2-4/25=0
We multiply all the terms by the denominator
100x^2*25-4=0
Wy multiply elements
2500x^2-4=0
a = 2500; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·2500·(-4)
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{40000}=200$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200}{2*2500}=\frac{-200}{5000} =-1/25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200}{2*2500}=\frac{200}{5000} =1/25 $
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